Good for them, Ralph is one of the nicest guys I've ever met.  Very strong. Don't ever try to  take a basketball from him if you tie up, he can jerk your arms completely out of joint. 

 Just chuck it!

 173 is very very good for this time of year

He will be 200+ (like Ralph was at USC) thrower for CSUB

CSUB has really strengthened its throwing events over the years.

I wonder who  "clued" Charlie in to the vast amount of points to be gained by even one shcolarship guy doing Hammer, Disc, Shot, even Javelin?

(hint: a lot....... and if you get three of them.... and sweep 3 or even 4 events? WOW!)

 Anglo, Ralph is relatively short for a thrower too

The formula (can't remember it exactly) for inches of radius equates to one inch equaling several feet in distance.

Think about it.

Its like the little Jap dude who used to be one of first  "four turners" in Hammer throwing in the 250 range years ago. I calculated once he could have been in 275+ range if he were just 6 footer!

Ralph is indeed a stud.

I've drank bock beers with him but haven't played bassetball!

 I hope I remember this correctly but I think Ralph told me he was a  member of the Italian Olympic team as a discus man. 

Yes. He is Discus thrower,  Anglo. But formulaes are the same .

 An athlete starts to swing a hammer in a 2m radius circle which is tilted up on one side. Each complete 360 degree swing takes 0.71s. The angle of the plane of the circle to the horizontal is 45 degrees.

The hammer is released at a height of 1.5m from the ground, at an angle of 45 degrees to the horizontal, while travelling at 18m/s. How far away does it land, assuming g=10ms-2

I started by coming up with parametric equations, which give the vertical (y) and horizontal (x) displacement as a function of time (t).


x=18t sin(45)
y=18t cos(45) - 5t^2


Since it was released from a heigh of 1.5m off the ground, the ground corrosponds to a displacement of -1.5m. So i set y=-1.5 and solved for t, giving t=2.658s. Then using this value in my 'x' equation, i get a horizontal displacement of 33.8m.

Now, did I flip flop the sign and cos or make a rounding error (in my answer?) You see, I'm coming out different than when I calculated this way back when. I got out some of my old papers. I think it may be inconsistent rounding, however.

Maybe TonyH can answer?